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Statement 1: Nitrobenzene when reduced w...

Statement 1: Nitrobenzene when reduced with `"LiAl"H_(4)` gives Aniline.
Statement 2: o-methoxyaniline is more basic than p-methoxyaniline.
Statement 3: Guanidine is a strong neutral base.

A

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B

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C

FFT

D

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Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement one by one. ### Step 1: Evaluate Statement 1 **Statement 1:** Nitrobenzene when reduced with LiAlH₄ gives Aniline. - **Explanation:** Nitrobenzene (C₆H₅NO₂) can be reduced to aniline (C₆H₅NH₂) using reducing agents. However, lithium aluminum hydride (LiAlH₄) is not typically used for this reduction because it is a strong reducing agent that can react with the aromatic ring, which makes the reduction less selective. The more common method for reducing nitrobenzene to aniline is using catalytic hydrogenation or other milder reducing agents. Therefore, this statement is **false**. ### Step 2: Evaluate Statement 2 **Statement 2:** o-Methoxyaniline is more basic than p-methoxyaniline. - **Explanation:** In the case of methoxyanilines, the methoxy group (–OCH₃) is an electron-donating group through resonance. In o-methoxyaniline, the methoxy group is positioned ortho to the amino group, which can lead to steric hindrance and intramolecular hydrogen bonding that can reduce the availability of the lone pair on the nitrogen for protonation. In contrast, in p-methoxyaniline, the methoxy group is para to the amino group, allowing for better resonance stabilization and availability of the lone pair. Thus, p-methoxyaniline is more basic than o-methoxyaniline. Therefore, this statement is also **false**. ### Step 3: Evaluate Statement 3 **Statement 3:** Guanidine is a strong neutral base. - **Explanation:** Guanidine (H₂N-C(=NH)-NH₂) is indeed a strong base. It has a high pKb value, indicating that it readily accepts protons. The presence of multiple nitrogen atoms allows for resonance stabilization of the positive charge when it accepts a proton, making it a strong base. Additionally, guanidine is neutral, as it does not carry a formal charge in its stable form. Therefore, this statement is **true**. ### Conclusion - **Final Evaluation of Statements:** - Statement 1: False - Statement 2: False - Statement 3: True Thus, the correct answer is that the first two statements are false, and the third statement is true.
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