Home
Class 12
PHYSICS
A particle is moving along x-axis such t...

A particle is moving along x-axis such that its velocity varies with time according to `v=(3m//s^(2))t-(2m//s^(3))t^(2)`. Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.

Text Solution

AI Generated Solution

To solve the problem step by step, we need to find the velocity of the particle at \( t = 1 \) second and the average velocity over the interval from \( t = 0 \) to \( t = 5 \) seconds. ### Step 1: Find the velocity at \( t = 1 \) second The velocity function is given by: \[ v(t) = (3 \, \text{m/s}^2) t - (2 \, \text{m/s}^3) t^2 ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|40 Videos
  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - A)|50 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D)|15 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos

Similar Questions

Explore conceptually related problems

The velocity of a particle is zero at time t = 2s, then

A particle moves along X-axis in such a way that its coordinate X varies with time t according to the equation x = (2-5t +6t^(2))m . The initial velocity of the particle is

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^4)/4-2t^3+4t^2-7. Find when its velocity is maximum

A particle moves rectilinearly possessing a parabolic s-t graph. Find the average velocity of the particle over a time interval from t = 1/2 s to t = 1.5 s.

If acceleration a(t) = 3t^(2) and initial velocity u=0 m/s , then the velocity of the particle after time t=4 s

A particle is moving along x-axis. Its X-coordinate varies with time as, X=2t^2+4t-6 Here, X is in metres and t in seconds. Find average velocity between the time interval t=0 to t=2s.

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Distance travelled by particle in 0 to 3 second time interval is :

A particle starts moving rectilinearly at time t=0 such that its velocity v changes with time t according to the equation v=t^(2)-t , where t is in seconds and v in s^(-1) . Find the time interval for which the particle retards.

A particle is moving on a straight line with velocity (v) as a function of time (t) according to relation v = (5t^(2) - 3t + 2)m//s . Now give the answer of following questions : Velocity of particle at t = 3 sec. is :

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-