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A car was movig at a rate of 18 kmh^(-1)...

A car was movig at a rate of `18 kmh^(-1)` . When the brakes were applied, it comes to rest in a distance of 100 m. Calculate the retardation produced by the brakes.

Text Solution

Verified by Experts

Using the equaiton of motion
`v^(2)-u^(2)=2as" …(i)"`
`v=0, u=18km//h=5m//s, S=100m`
So, substituting the values in equation (i) we get
`"Therefore, "a=(-5xx5)/(2xx100)=-(1)/(8)=-0.125m//s^(2)`
So, the retardation produced by the brakes is `0.125m//s^(2)`.
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