The velocity of an object is changing with time and relation is given by the following equation.
`v=2t+3t^(2)`
Calculate the position of the object from the origin at t = 2 s.
Assume particle to be at origin at t = 0

Explanation

To solve the problem of finding the position of the object from the origin at \( t = 2 \) seconds, given the velocity function \( v = 2t + 3t^2 \), we will follow these steps:

### Step 1: Understand the relationship between velocity and position
The velocity \( v \) is the derivative of the position \( x \) with respect to time \( t \). Therefore, we can write:
\[ v = \frac{dx}{dt} \]
Given \( v = 2t + 3t^2 \), we can substitute this into the equation:
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