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A stone is thrwon vertically upwards. On...

A stone is thrwon vertically upwards. On its way is passes point A with a speed v and passes point B, 30 m higher than A with speed `(v)/(2)`. Find (i) The speed v (ii) The maximum height reached by the stone above point B.

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To solve the problem step by step, we will use the principles of kinematics. ### Step 1: Identify the known quantities - Speed at point A: \( v \) - Speed at point B: \( \frac{v}{2} \) - Height difference between points A and B: \( s = 30 \, \text{m} \) - Acceleration due to gravity: \( g \) (approximately \( 10 \, \text{m/s}^2 \)) ...
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