Home
Class 12
PHYSICS
A boat can be rowed in still water at a ...

A boat can be rowed in still water at a speed u. The boat is moving downstream in a river in which water flows at a speed v. There is raft floating in water and therefore moving along with water at speed v. Let the boat overtakes the raft at the moment t = 0.
Let the boat turns back at time `t=t_(0)` and starts moving towards the raft. The separation between the raft and boat after a time interval t' measured from the moment of turning back is

A

`ut_(0)-ut'`

B

`ut_(0)-(u+v)t'`

C

`ut_(0)-vt'`

D

`ut_(0)-ut'+vt'`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of the boat and the raft step by step. ### Step-by-Step Solution: 1. **Understanding the Initial Setup**: - The boat can row in still water at a speed \( u \). - The river flows at a speed \( v \). - When the boat is moving downstream, its effective speed is \( u + v \) (boat speed + river speed). - The raft moves with the river at speed \( v \). 2. **Distance Traveled by the Boat Before Turning Back**: - The boat overtakes the raft at \( t = 0 \). - Let the boat turn back at time \( t = t_0 \). - The distance traveled by the boat downstream in time \( t_0 \) is given by: \[ \text{Distance}_{\text{boat}} = (u + v) t_0 \] - This distance is the initial separation between the boat and the raft when the boat turns back. 3. **Boat's Speed When Moving Upstream**: - After turning back, the boat moves upstream against the river's current. - The effective speed of the boat when moving upstream is: \[ \text{Speed}_{\text{upstream}} = u - v \] 4. **Distance Traveled by the Boat and Raft After Turning Back**: - Let \( t' \) be the time interval after the boat turns back. - The distance traveled by the boat upstream during time \( t' \) is: \[ \text{Distance}_{\text{boat}} = (u - v) t' \] - The distance traveled by the raft downstream during the same time \( t' \) is: \[ \text{Distance}_{\text{raft}} = v t' \] 5. **Calculating the Separation After Time \( t' \)**: - The initial separation when the boat turns back is \( (u + v) t_0 \). - After time \( t' \), the separation between the boat and the raft becomes: \[ \text{Separation} = \text{Initial Separation} - \text{Distance}_{\text{raft}} + \text{Distance}_{\text{boat}} \] - Substituting the distances: \[ \text{Separation} = (u + v) t_0 - v t' + (u - v) t' \] - Simplifying this expression: \[ \text{Separation} = (u + v) t_0 - v t' + u t' - v t' \] \[ = (u + v) t_0 - (v + v) t' + u t' \] \[ = (u + v) t_0 - 2v t' + u t' \] \[ = (u + v) t_0 - u t' \] 6. **Final Expression for Separation**: - The final expression for the separation between the raft and the boat after time \( t' \) is: \[ \text{Separation} = u t_0 - u t' \] ### Conclusion: The correct answer is: \[ \text{Separation} = u t_0 - u t' \]

To solve the problem, we need to analyze the motion of the boat and the raft step by step. ### Step-by-Step Solution: 1. **Understanding the Initial Setup**: - The boat can row in still water at a speed \( u \). - The river flows at a speed \( v \). - When the boat is moving downstream, its effective speed is \( u + v \) (boat speed + river speed). ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|40 Videos
  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - A)|50 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D)|15 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos

Similar Questions

Explore conceptually related problems

A boat can be rowed in still water at a speed u. The boat is moving downstream in a river in which water flows at a speed v. There is raft floating in water and therefore moving along with water at speed v. Let the boat overtakes the raft at the moment t = 0. The distance between the boat and raft at a later instant of time t is

A boat can be rowed in still water at a speed u. The boat is moving downstream in a river in which water flows at a speed v. There is raft floating in water and therefore moving along with water at speed v. Let the boat overtakes the raft at the moment t = 0. Let the boat turns back at time t = t_(0) and starts moving towards the raft. After how much time, measured from the moment of turning back the boat will cross the raft again ? Option 1 t_(0) Option 2 (ut_(0))/(u+v) Option 3 (vt_(0))/(u+v) Option 4 ((v+v)t_(0))/(u-v)

When we jump out of a boat standing in water it moves

A boat is being rowed in a river. Air is also blowing. Direction of velocity vectors of boat, water and air in ground frame are as shown in diagram.

A boat goes 12 km upstream and 40 km downstream in 8 hours. It can go 16 km upstream and 32 km downstream in the same time. Find the speed of the boat in still water and the speed of the stream

A boat, which can travel at a speed of 8 km/h in still water on a lake, is rowing in the flowing water in river. If the stream speed is 3 km/h, how fast the boat can cross a tree on the shore in traveling upstream ?

A boat is moving with a velocity 3 hat i+ 4hat j with respect to ground. The water in the river is moving with a velocity -3 hat i - 4 hat j with respect to ground. The relative velocity of the boat with respect to water is.

A boat is moving with a velocity v_(bw)=5 km//hr relative to water. At time t=0 .the boat passes through a piece of cork floating in water while moving down stream.If it turns back at time t_(1)=30 min . a) when the boat meet the cork again? b) The distance travelled by the boat during this time.

A man floating on a raft in water flowing at 2kmph observes a motor lauch overtaking him at t = 0. Then lauch travels with the speed of 20kmp relative to still water . After travelling for a time of 1 hr , the lauch turns back towards raft.How far from from the original point of crossing do they meet and what is the total time elapsed ?