An object travels 20 m in 4 s and then another 20 m in 10 s. What is the average speed of the object?

Explanation

To find the average speed of the object, we can follow these steps:

### Step 1: Identify the distances and times
The object travels two distances:
- First distance \(d_1 = 20 \, \text{m}\) in \(t_1 = 4 \, \text{s}\)
- Second distance \(d_2 = 20 \, \text{m}\) in \(t_2 = 10 \, \text{s}\)

### Step 2: Calculate the total distance
The total distance \(D\) covered by the object is the sum of the two distances:
\[ D = d_1 + d_2 = 20 \, \text{m} + 20 \, \text{m} = 40 \, \text{m} \]

### Step 3: Calculate the total time
The total time \(T\) taken by the object is the sum of the two times:
\[ T = t_1 + t_2 = 4 \, \text{s} + 10 \, \text{s} = 14 \, \text{s} \]

### Step 4: Calculate the average speed
The average speed \(v_{\text{avg}}\) is defined as the total distance divided by the total time:
\[ v_{\text{avg}} = \frac{D}{T} = \frac{40 \, \text{m}}{14 \, \text{s}} = \frac{20}{7} \, \text{m/s} \]

### Final Answer
Thus, the average speed of the object is:
\[ v_{\text{avg}} = \frac{20}{7} \, \text{m/s} \approx 2.86 \, \text{m/s} \]

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