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Under what conditions (s) is the magnitude of average velocity of an object equal to its average speed ?

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To determine the conditions under which the magnitude of average velocity of an object is equal to its average speed, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Definitions**: - Average Velocity (V_avg) is defined as the total displacement divided by the total time taken: \[ V_{avg} = \frac{\text{Displacement}}{\text{Time}} \] - Average Speed (S_avg) is defined as the total distance traveled divided by the total time taken: \[ S_{avg} = \frac{\text{Distance}}{\text{Time}} \] 2. **Identify the Relationship**: - For the average velocity and average speed to be equal, we need: \[ |V_{avg}| = S_{avg} \] - This implies: \[ \frac{\text{Displacement}}{\text{Time}} = \frac{\text{Distance}}{\text{Time}} \] - Simplifying this gives: \[ \text{Displacement} = \text{Distance} \] 3. **Conditions for Equality**: - Displacement is equal to distance when the object moves in a straight line without changing direction. This means: - The object must travel in a single direction. - There should be no turns or changes in the path. 4. **Conclusion**: - Therefore, the magnitude of average velocity is equal to the average speed when the object moves in a straight line in a single direction without changing its path. ### Summary: The conditions under which the magnitude of average velocity equals average speed are: - The object moves in a straight line. - The object does not change direction.

To determine the conditions under which the magnitude of average velocity of an object is equal to its average speed, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Definitions**: - Average Velocity (V_avg) is defined as the total displacement divided by the total time taken: \[ V_{avg} = \frac{\text{Displacement}}{\text{Time}} ...
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