A metal rod of length `50cm` having mass `2kg` is supported on two edges placed `10cm` from each end. A `3kg` load is suspended at `20cm` from one end. Find the reactions at the edges (take `g=10m//s^(2)`)

Explanation

To solve the problem step by step, we will analyze the forces acting on the metal rod and apply the principles of static equilibrium.

### Step 1: Identify the Given Data
- Length of the rod (L) = 50 cm
- Mass of the rod (m1) = 2 kg
- Mass of the load (m2) = 3 kg
- Distance of the supports from the ends = 10 cm
- Gravitational acceleration (g) = 10 m/s²
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