Home
Class 12
PHYSICS
A disc of mass M and radius R as shown i...

A disc of mass `M` and radius `R` as shown in figure has some points on it. `C` is the cenre of disc, `AB` is the chord and `O` is mid point of chord. The notation `I_(A)` means moment of inertia of the disc about axis passing through point `A` and pependicular to the plane of disc. Choose the correct option(s)

A

`I_(A)=I_(C )+M(AO)^(2)`

B

`I_(B)=I_(C )+M(BC)^(2)`

C

`I_(A)=I_(0)+M(OA)^(2)`

D

`I_(B)=I_(0)+M(OA)^(2)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - D) Linked Comprehension Type Questions|20 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - E) Assertion-Reason Type Questions|12 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - B) Objective Type Questions (One option is correct)|60 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|21 Videos

Similar Questions

Explore conceptually related problems

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

The mass of a disc is 700 gm and its radius of gyration is 20 cm. What is its moment of inertia if it rotates about an axis passing through its centre and perpendicular to the face of the disc?

Moment of inertia of a thin semicircular disc (mass - M & radius = R) about an axis through point O and perpendicular to plane of disc, is given by : .

Moment of inertia of a thin semicircular disc (mass - M & radius = R) about an axis through point O and perpendicular to plane of disc, is given by : .

The surface mass density of a disc of radius a varies with radial distance as sigma = A + Br where A & B are positive constants then moment of inertia of the disc about an axis passing through its centre and perpendicular to the plane

The moment of inertia of a uniform semicircular disc of mass M and radius r about a line perpendicular to the plane of the disc through the center is

Surface mass density of disc of mass m and radius R is Kr^(2) . Then its moment of inertia w.r.t. axis of rotation passing through center and perpendicular to the plane of disc is :

Calculate the moment of inertia of a.unifprm disc of mass 0.4 kg and radius 0.1m about an axis passing through its edge and perpendicular to the plane of die disc ?

A uniform disc (of mass M and radius a ) has a hole (of radius b ) drilled through it. The centre of the hole is at a distance c from the centre of the original disc. What is the moment of inertia of the disc about an axis through the centre of the disc and perpendicular to its plane ?

A disc of mass m and radius R, is placed on a smooth text service fixed surface . Point A is the geometrical centre of the disc while point B is the centre of mass of the disc . The moment of inertia of the dics about an axis through its centre of mass and perpendicular to the plane of the figure is I .A constant force F is applied to the top of the disc . The acceleration of the centre A of the disc at the instant B is below A (on the same vertical line ) will be :

AAKASH INSTITUTE ENGLISH-SYSTEM OF PARTICLES AND ROTATIONAL MOTION-Assignment (Section - C) Objective Type Questions (More than one option are correct)
  1. Two projectiles collide in air, then for just after and before the col...

    Text Solution

    |

  2. Two particles A and B of masses 2kg and 3kg moving on a smooth horizon...

    Text Solution

    |

  3. A particle strikes a smooth horizontal surface at an angle theta gt 0 ...

    Text Solution

    |

  4. A girl throws the ball with horizontal velocity 2m//s at the moment t=...

    Text Solution

    |

  5. A fan is switched on and it accelerates at a constant angular accelera...

    Text Solution

    |

  6. A block of mass m is connected to another block of mass M by a massles...

    Text Solution

    |

  7. A disc of mass M and radius R as shown in figure has some points on it...

    Text Solution

    |

  8. A rod of mass m and length L is pivoted at the bottommost point O and ...

    Text Solution

    |

  9. A rod of mass m and length L is pivoted at a point O and kept in horiz...

    Text Solution

    |

  10. A horizontal rod of mass M and length L is tied to two verticle string...

    Text Solution

    |

  11. A disc of radius R is moving on a rough horizontal surface with veloci...

    Text Solution

    |

  12. A disc of given some velocity up the incline so that it goes up, stops...

    Text Solution

    |

  13. A ring of mass m and radius R is placed on a rough horizontal surface ...

    Text Solution

    |

  14. A solid sphere of mass m and radius R is released from top of an incli...

    Text Solution

    |

  15. On an uniform cylinder of mass m and radius R a constant horizontal fo...

    Text Solution

    |

  16. A particle of mass m is moving with constant velocity v(0) along the l...

    Text Solution

    |

  17. A disc of mass m and radius R rotating with angular speed omega(0) is ...

    Text Solution

    |

  18. A block of mass m moves on a horizontal rough surface with initial vel...

    Text Solution

    |

  19. A uniform rod of length l and mass 2 m rests on a smooth horizontal ta...

    Text Solution

    |

  20. A disc of mass m and radius R is kept on a smooth horizontal surface w...

    Text Solution

    |