Home
Class 12
PHYSICS
A particle collides a horizontal smooth ...

A particle collides a horizontal smooth surface with velocity `vecv_(1)`, `hatn` is the unit vector perpendicular to the surface. If `e` is the coefficient of restitution, then find the velocity vector in which particle is rebounded.

Text Solution

Verified by Experts

`vecv_(1)-[vecv_(1)*hatn)(1+e)]hatn`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|63 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - I) Subjective Type Questions|8 Videos

  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D (Assertion and reason))|5 Videos

  • TEST 1

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|21 Videos

Similar Questions

Explore conceptually related problems

A ball moving with speed v collides with a horizontal smooth surface at an angle theta with normal to surface as shown in figure. If coefficient of restitution of collision is e, then find v'

A particle of mass m strikes a horizontal smooth floor with velocity u making an angle theta with the floor and rebound with velocity v making an angle theta with the floor. The coefficient of restitution between the particle and the floor is e . Then

A smooth sphere is moving on a horizontal surface with velocity vector 2hati+2hatj immediately before it hits a vertical wall. The wall is parallel to hatj and the coefficient of restitution of the sphere and the wall is e=1/2 . Find the velocity of the sphere after it hits the wall?

A particle of mass m=1 kg collides with the end with velocity v_(0)=6 ms^(-1) of a spinning rod of mass 2m and length l=1 m at the end of the rod. If the coefficient of restitution of collision e=(2//3), find the a. velocity of the particle b. angular velocity of the rod just after the impact.

A particle strikes a smooth horizontal surface at an angle of 45^(@) with a velocity of 100m//s and rebounds. If the coefficient of restitution between the floor and the particle is 0.57 then the angle which the velocity of the particle after it rebounds will make with the floor is

A glass ball collides with a smooth horizontal surface ( xz plane) with a velocity V = ai- bj . If the coefficient of restitution of collision be e , the velocity of the ball just after the collision will be

A smooth sphere is moving on a horizontal surface with velocity vector 3hat(i) + hat(j) immediately before it hits a vertical wall. The wall is parallel to the vector hat(j) and the coefficient of restitution between the wall and sphere is (1)/(3) . The velocity vector of the sphere after it hits the wall is :-

A body falls on a surface of coefficient of restitution 0.6 from a height of 1 m . Then the body rebounds to a height of

A ball collides perpendicularly with a vertical wall with speed v, and rebounds with speed v, as shown in the figure. If v_1 > v_2 then coefficient of restitution(e) is

A particle is projected with velocity u at angle theta with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.