Three particles having their masses in the ratio `1 : 3 : 5` are kept at the vertices of a triangle `ABC`. Coordinate of `A`, `B` and `C` are `(9,-3)`, `(3,4)` and `(0,0)`. Find the coordinates of the centre of mass.
Hint. `x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i))`, `y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))`

Explanation

To find the coordinates of the center of mass of three particles located at the vertices of triangle ABC, we will follow these steps:

### Step 1: Identify the coordinates and masses
The coordinates of the vertices are:
- A (x1, y1) = (9, -3)
- B (x2, y2) = (3, 4)
- C (x3, y3) = (0, 0)

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