Calculate the instantaneous power of a body rotating with angular velocity of `20rad//s^(-2)`, when an external torque of `5 Nm` is applied to it.
Hint : `P=tau omega`.

Explanation

To calculate the instantaneous power of a body rotating with a given angular velocity when an external torque is applied, we can use the formula:

\[ P = \tau \cdot \omega \]

where:
- \( P \) is the instantaneous power,
- \( \tau \) is the torque,
- \( \omega \) is the angular velocity.
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