The gravitational field due to a mass distribution is given by `vec(l)=(k)/(x^(2))hat(i)`, where k is a constant. Assuming the potential to be zero at infinity, find the potential at a point x = a.

Explanation

To find the gravitational potential at a point \( x = a \) given the gravitational field \( \vec{E} = \frac{k}{x^2} \hat{i} \), we can follow these steps:

### Step 1: Relate gravitational field to potential
The relationship between gravitational field \( \vec{E} \) and gravitational potential \( V \) is given by:
\[ \vec{E} = -\frac{dV}{dx} \]
This means that the gravitational field is the negative gradient of the potential.
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