STATEMENT -1 : Time period of a satellite is inversely propertional to the square root of the mass of planet.
STATEMENT -2 : Self gravitational potential energy of earth is positive.
STATEMENT -3 : Orbital velocity of a satellite does depend upon the mass of planet.

Options

A. T T T
B. T F F
C. T F T
D. F F F

Answer

To analyze the three statements provided in the question, we will evaluate each statement one by one and derive the necessary conclusions.

### Step 1: Evaluate Statement 1
**Statement 1:** Time period of a satellite is inversely proportional to the square root of the mass of the planet.

**Analysis:**
The time period (T) of a satellite in orbit can be derived from Kepler's third law of planetary motion. The formula for the time period of a satellite is given by:

\[ T = 2\pi \sqrt{\frac{r^3}{GM}} \]

Where:
- \( T \) is the time period,
- \( r \) is the radius of the orbit,
- \( G \) is the gravitational constant,
- \( M \) is the mass of the planet.

From the formula, we can see that:

\[ T \propto \sqrt{\frac{r^3}{M}} \]

This indicates that the time period is directly proportional to the square root of the radius and inversely proportional to the square root of the mass of the planet. Therefore, Statement 1 is **True**.

### Step 2: Evaluate Statement 2
**Statement 2:** Self gravitational potential energy of Earth is positive.

**Analysis:**
The gravitational potential energy (U) of a mass in a gravitational field is given by:

\[ U = -\frac{GMm}{r} \]

Where:
- \( G \) is the gravitational constant,
- \( M \) is the mass of the Earth,
- \( m \) is the mass of the object,
- \( r \) is the distance from the center of the Earth.

This equation shows that the gravitational potential energy is negative. Therefore, Statement 2 is **False**.

### Step 3: Evaluate Statement 3
**Statement 3:** Orbital velocity of a satellite does depend upon the mass of the planet.

**Analysis:**
The orbital velocity (v) of a satellite can be derived from the balance of gravitational force and centripetal force:

\[ F = \frac{GMm}{r^2} = \frac{mv^2}{r} \]

From this, we can derive the orbital velocity:

\[ v = \sqrt{\frac{GM}{r}} \]

This shows that the orbital velocity is directly proportional to the square root of the mass of the planet (M). Therefore, Statement 3 is **True**.

### Conclusion
- **Statement 1:** True
- **Statement 2:** False
- **Statement 3:** True

Thus, the overall evaluation of the statements is:
- Statement 1: True
- Statement 2: False
- Statement 3: True

### Final Answer
The correct answer is: True, False, True.

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