Home
Class 12
PHYSICS
Two point particles of mass m and 2m are...

Two point particles of mass m and 2m are initially separated by a distance 4a. They are then released to become free to move. Find the velocities of both the particles when the distance between them reduces to a.

Text Solution

AI Generated Solution

To solve the problem of finding the velocities of two point particles of mass \( m \) and \( 2m \) when the distance between them reduces from \( 4a \) to \( a \), we will use the principles of conservation of linear momentum and conservation of mechanical energy. ### Step-by-Step Solution: 1. **Initial Setup**: - Let the mass \( m_1 = m \) and mass \( m_2 = 2m \). - The initial distance between them is \( 4a \). - When they are released, they will move towards each other due to gravitational attraction. ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION -J (Aakash Challengers Questions)|6 Videos
  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOUR SELF|33 Videos
  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION -H (Multiple True - False Type Questions)|5 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D|9 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos

Similar Questions

Explore conceptually related problems

The center of mass of a system of two particles divides the distance between them.

The center of mass of a system of two particles divides the distance between them.

Two particles of masses m and M are initially at rest at an infinite distance apart. They move towards each other and gain speeds due to gravitational attraction. Find their speeds when the separation between the masses becomes equal to d.

A particle of mass 100 gm and charge 2muC is released from a distance of 50 cm from a fixed charge of 5muC . Find the speed of the particle when its distance from the fixed charge becomes 3 m.

Two particles of masses m_(1) and m_(2) (m_(1) gt m_(2)) are separated by a distance d. The shift in the centre of mass when the two particles are interchanged.

Two particles of mass m and M are initialljy at rest at infinite distance. Find their relative velocity of approach due to gravitational attraction when d is their separation at any instant

Two point charges, each of mass m and charge q are released when they are at a distance d from each other. What is the speed of each charged particle when they are at a distance 2r ?

A particle of mass m and charge q is placed at rest in a uniform electric field E and then released, the kinetic energy attained by the particle after moving a distance y will be

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two points mass m and 2m are kept at a distance a . Find the speed of particles and their relative velocity of approach when separation becomes a//2 .