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A square lead slab of side 50 cm and thi...

A square lead slab of side 50 cm and thickness 10.0 cm is subjected to a shearing force (on its narrow face) of magnitude `9.0xx10^(4)` N. The lower edge is riveted to the floor as shown in figure. How much is the upper edge displaced, if the shear modulus of lead is `5.6xx10^(8)Pa` ?

Text Solution

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Here, `L=50 cm=50xx10^(-2)m, G=5.6xx10^(9)Pa, F=9.0xx10^(4)N`
Area of the face on which force is applied, `a=50xx10="500 sq. cm = 0.05 m"^(2)`
If `DeltaL` is the displacement of the upper edge of the slab due to tangential force F applied, then
`G=(F//a)/(DeltaL/L)or DeltaL=(FL)/(Ga)=(9xx10^(4)xx50xx10^(-2))/(5.6xx10^(9)xx0.05`
`G=1.6xx10^(-4)m`
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