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Water is flowing in a pipe of radius 1.5...

Water is flowing in a pipe of radius 1.5 cm with an average velocity 15 cm `s^(-1)`. What is the nature of flow? Given coefficient of viscosity of water is `10^(-3)` kg `m^(-1) s^(-1)` and its density is `10^(3)` kg `m^(-3)`

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To determine the nature of the flow of water in the pipe, we will calculate the Reynolds number (R). The Reynolds number helps us identify whether the flow is laminar or turbulent. ### Step-by-Step Solution: 1. **Identify the given values**: - Radius of the pipe (r) = 1.5 cm = 0.015 m (convert cm to m) - Average velocity (V) = 15 cm/s = 0.15 m/s (convert cm/s to m/s) - Coefficient of viscosity (η) = \(10^{-3}\) kg/(m·s) ...
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