The average mass that must be lifted by a hydraulic press is `80 "kg"`.If the radius of the larger piston is five times that of the smaller piston, what is the minimum force that must be applied?

Explanation

To solve the problem of finding the minimum force that must be applied to a hydraulic press, we can follow these steps:

### Step 1: Understand the relationship between force and area in a hydraulic press.
In a hydraulic press, the pressure applied on both pistons is the same. This can be expressed mathematically as:
\[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \]
where:
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