Water flows through a horizontal pipe of varying area of cross section at the rate 15 cubic metre per minute. Find the radius of pipe where water velocity is 3 `ms^(-1)`

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Convert the flow rate from cubic meters per minute to cubic meters per second.
Given that the flow rate is 15 cubic meters per minute, we need to convert this to cubic meters per second.

\[ \text{Flow rate (Q)} = \frac{15 \text{ m}^3}{1 \text{ min}} = \frac{15 \text{ m}^3}{60 \text{ s}} = 0.25 \text{ m}^3/\text{s} \]
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