A metal block of area 0.10 `m^(2)` placed at a table, is connected to a 0.010 kg mass via a string that passes over an ideal pulley. Th pulley is fixed at the edge of the table. A liquid with a film of thickness 0.30 mm is placed between the block and the table. If the coefficient of viscosity of the liquid is `3.45 xx 10^(-3)` Pa s, with what constant velocity does the block move when released?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Understand the forces acting on the block
When the metal block is released, it will experience two main forces:
- The gravitational force acting downwards due to the mass connected to it.
- The viscous force acting upwards due to the liquid film between the block and the table.

### Step 2: Calculate the gravitational force (Weight)
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