What is the terminal velocity of a copper ball of radius 2.0 mm, which falls through an oil tank? Given that density of oil = `1.5 xx 10^(3)` kg `m^(-3)`, density of copper `= 8.9 xx 10^(3) kg m^(-3)` and viscosity of oil is 0.99 kg `m^(-1)s^(-1)`.

Explanation

To find the terminal velocity of a copper ball falling through an oil tank, we can use the formula for terminal velocity in a viscous fluid:

\[ V_t = \frac{2}{9} \cdot \frac{R^2 (\rho - \sigma) g}{\eta} \]

Where:
- \( V_t \) = terminal velocity
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