Find the excess pressure inside a liquid drop of radius 2 cm, if the surface tension of water is 0.073 N `m^(-1)`

Explanation

To find the excess pressure inside a liquid drop, we can use the formula for excess pressure in a droplet, which is given by:

\[ \Delta P = \frac{2S}{R} \]

where:
- \(\Delta P\) is the excess pressure,
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