Find the total pressure inside a sperical air bubble of radius 0.2 mm. The bubble is at a depth 5 cm below the surface of a liquid of density `2 xx 10^(3)` kg `m^(-3)` and surface tension 0.082 N `m^(-1)`. (Given : atmospheric pressure = 1.01 `xx 10^(5) Nm^(-2)`)
Hint : `P_(i) = P_(o) + (2S)/(R)`
`P_(o)` = atmospheric pressure + gauge pressure of liquid column.

Explanation

To find the total pressure inside a spherical air bubble at a certain depth in a liquid, we can use the formula:

\[ P_i = P_o + \frac{2S}{R} \]

Where:
- \( P_i \) is the total pressure inside the bubble.
- \( P_o \) is the pressure exerted on the bubble from the outside.
- \( S \) is the surface tension of the liquid.
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