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Select the incorrect option (T = surface...

Select the incorrect option (T = surface tension, R = radius of drop, bubble, meniscus)

A

Excess pressure inside a liquid drop in air is equal to `(2T)/(R)`

B

Excess presure inside a liquid bubbles in air is equal to `(2T)/(R)`

C

Excess pressure for spherical liquid meniscus is `(4T)/(R)`

D

Excess pressure for cylindrical bubble in air is `(4T)/(R)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of selecting the incorrect option regarding the excess pressure in different fluid situations, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Understanding Surface Tension and Excess Pressure**: - Surface tension (T) is a property of the liquid that causes it to behave like a stretched elastic membrane. - Excess pressure (ΔP) across a curved surface is related to surface tension and the radius of curvature. 2. **Analyzing Option 1**: - **Statement**: Excess pressure inside a liquid drop in air is equal to \( \frac{2T}{R} \). - **Analysis**: A liquid drop in air has one curved surface. The formula for excess pressure for a drop is indeed \( \Delta P = \frac{2T}{R} \). - **Conclusion**: Option 1 is **correct**. 3. **Analyzing Option 2**: - **Statement**: Excess pressure inside a liquid bubble in air is equal to \( \frac{2T}{R} \). - **Analysis**: A liquid bubble has two surfaces (inner and outer). The correct formula for excess pressure in a bubble is \( \Delta P = \frac{4T}{R} \) (since there are two surfaces contributing to the pressure). - **Conclusion**: Option 2 is **incorrect**. 4. **Analyzing Option 3**: - **Statement**: Excess pressure of a spherical liquid meniscus is \( \frac{4T}{R} \). - **Analysis**: A spherical meniscus has only one surface, so the correct excess pressure is \( \Delta P = \frac{2T}{R} \). - **Conclusion**: Option 3 is **incorrect**. 5. **Analyzing Option 4**: - **Statement**: Excess pressure for a cylindrical bubble in air is \( \frac{4T}{R} \). - **Analysis**: A cylindrical bubble has two surfaces, so the correct excess pressure is \( \Delta P = \frac{2T}{R} \). - **Conclusion**: Option 4 is **incorrect**. ### Final Conclusion: The incorrect options are **2, 3, and 4**.
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