Statement-1 : If there is a soap bubble in air then excess pressure inside it is `(4T)/(R)`, where T is surface tension of soap and R is the radius of the bubble.
Statement-2 : If there is a water drop in air then excess pressure inside it is `(2T)/(R)`
Statement-3 : If there is an air bubble in water then excess pressure inside it is `(4T)/(R)`

Options

A. T T T
B. T T F
C. T F F
D. T F T

Answer

To solve the problem, we need to analyze each statement regarding the excess pressure inside soap bubbles, water drops, and air bubbles in water.

### Step-by-Step Solution:

1. **Understanding Excess Pressure in Soap Bubbles:**
- A soap bubble consists of two surfaces (inner and outer).
- The formula for excess pressure inside a soap bubble is given by:
\[ \Delta P = \frac{4T}{R} \]
- Here, \(T\) is the surface tension of the soap, and \(R\) is the radius of the bubble.
- **Conclusion:** Statement 1 is **True**.

2. **Understanding Excess Pressure in Water Drops:**
- A water drop in air has only one surface (the outer surface).
- The formula for excess pressure inside a water drop is given by:
\[ \Delta P = \frac{2T}{R} \]
- Here, \(T\) is the surface tension of water, and \(R\) is the radius of the drop.
- **Conclusion:** Statement 2 is **True**.

3. **Understanding Excess Pressure in Air Bubbles in Water:**
- An air bubble in water also has only one surface (the outer surface of the bubble).
- The formula for excess pressure inside an air bubble in water is:
\[ \Delta P = \frac{2T}{R} \]
- Here, \(T\) is the surface tension of water, and \(R\) is the radius of the bubble.
- **Conclusion:** Statement 3 is **False** because it incorrectly states that the excess pressure is \(\frac{4T}{R}\).

### Final Conclusion:
- Statement 1 is True.
- Statement 2 is True.
- Statement 3 is False.