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The speed of a particle executing SHM wi...

The speed of a particle executing SHM with amplitude of displacement 5 cm is `3 cm //s ` at a distance 2.5 cm from mean position. What will be its speed at a distance `2.5 sqrt(3)` from mean position?

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To solve the problem step by step, we will use the formula for the speed of a particle in Simple Harmonic Motion (SHM): \[ v = \omega \sqrt{A^2 - x^2} \] where: - \( v \) is the speed of the particle, - \( \omega \) is the angular frequency, - \( A \) is the amplitude, ...
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