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If the length of a simple pendulum is in...

If the length of a simple pendulum is increased by 2%, then the time period

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`%` change is very less
So , `(DeltaT) /( T) = (1)/(2)(DeltaL)/(L)`
Here, T is time in second for the whole day` = 86400s`
Given `( DeltaL )/(L) = 2%= (2)/(100)`
`:. (DeltaT)/( 86400)= (1)/(2) xx ( 2)/( 100) `
`:. DeltaT = 864 s`
As length is increasing,the time period T will becomelarge and the clock will go slow, so it will lose 864 s.
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