Home
Class 12
PHYSICS
A spring of spring constant k is cut in ...

A spring of spring constant k is cut in three equal pieces. The spring constant of each part will be

A

`(k)/(3)`

B

`3k`

C

`k`

D

`(k)/(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the spring constant of each part when a spring of spring constant \( k \) is cut into three equal pieces, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Initial Condition**: - We have a spring of length \( L \) and spring constant \( k \). - The relationship between the spring constant \( k \) and the length \( L \) is given by the formula: \[ k \cdot L = \text{constant} \] 2. **Cut the Spring**: - The spring is cut into three equal pieces. Therefore, the length of each piece becomes: \[ \text{Length of each piece} = \frac{L}{3} \] 3. **Define the New Spring Constant**: - Let the new spring constant of each piece be \( k' \). - According to the spring constant relationship, for each piece, we have: \[ k' \cdot \left(\frac{L}{3}\right) = \text{constant} \] 4. **Set Up the Equation**: - For the original spring, the relationship can be expressed as: \[ k \cdot L = k' \cdot \left(\frac{L}{3}\right) \] 5. **Solve for the New Spring Constant**: - Rearranging the equation gives: \[ k' = k \cdot \frac{L}{\frac{L}{3}} = k \cdot 3 = 3k \] 6. **Conclusion**: - The spring constant of each of the three equal pieces is: \[ k' = 3k \] ### Final Answer: The spring constant of each part will be \( 3k \).
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-B )|25 Videos
  • OSCILLATIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-C )|11 Videos
  • OSCILLATIONS

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|86 Videos
  • NUCLEI

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|10 Videos
  • PHYSICAL WORLD

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (Section-B)|4 Videos

Similar Questions

Explore conceptually related problems

A light spring of spring constant k is cut into two equal halves. Each half is connected in parallel then net spring constant of the combination is :

A spring of spring constant k is cut into n equal parts, out of which r parts are placed in parallel and connected with mass M as shown in figure. The time period of oscillatory motion of mass M is:

A spring of certain length and having spring constant k is cut into two pieces of length in a ratio 1:2 . The spring constants of the two pieces are in a ratio :

Two springs of spring constants K_(1) and K_(2) are joined in series. The effective spring constant of the combination is given by

Two springs of spring constants K_(1) and K_(2) are joined in series. The effective spring constant of the combination is given by

The periodic time of a mass suspended by a spring (force constant k) is T. The spring be cut into three equal pieces. If the same mass be suspended from one piece, what will be the periodic time ?

If a spring has time period T, and is cut into (n) equal parts, then the time period of each part will be.

A spring of force constant 'k' is cut into four equal parts one part is attached with a mass m. The time period of oscillation will be

A solid sphere rolls without slipping and presses a spring of spring constant k as shown in figure. Then, the compression in the spring will be

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

AAKASH INSTITUTE ENGLISH-OSCILLATIONS-ASSIGNMENT ( SECTION -A)
  1. A body of mass 8 kg performs S.H.M. of amplitude 60 cm. The restoring ...

    Text Solution

    |

  2. A spring of force constant 600 Nm^(-1) is mounted on a horizontal tabl...

    Text Solution

    |

  3. A spring of force constant 600 Nm^(-1) is mounted on a horizontal tabl...

    Text Solution

    |

  4. A mass of 1.5 kg is connected to two identical springs each of force c...

    Text Solution

    |

  5. A mass of 1.5 kg is connected to two identical springs each of force c...

    Text Solution

    |

  6. A spring of spring constant k is cut in three equal pieces. The spring...

    Text Solution

    |

  7. Figure-1 to Figure -4 shows four different spring arrangements . Mass ...

    Text Solution

    |

  8. Two identical springs have the same force constant of 147Nm^(-1). What...

    Text Solution

    |

  9. The frequency of oscillation of amass m suspended by a spring is v(1)....

    Text Solution

    |

  10. The total energy of a simple pendulum is x. When the displacement is ...

    Text Solution

    |

  11. The acceleration of a body in SHM is

    Text Solution

    |

  12. In SHM, the plot of acceleration y at time t and displacement x for on...

    Text Solution

    |

  13. A uniform rod ofmass M and length L is hanging from its one end fre...

    Text Solution

    |

  14. An ideal liquid having length of liquid column l is column in V-shape...

    Text Solution

    |

  15. In the arrangement shown in figure a solid sphere is attached to sprin...

    Text Solution

    |

  16. A person is standing on an open car moving with a constant velocity of...

    Text Solution

    |

  17. A disc is hanging from pin hole as shown in figure and displaced sligh...

    Text Solution

    |

  18. A point mass m is supended at the end of a massless wire of length Lan...

    Text Solution

    |

  19. A heavy brass sphere is hung from a weightless inelastic string and us...

    Text Solution

    |

  20. Two pendulums of lengths 1.44 m and 1 m start oscillating together. Af...

    Text Solution

    |