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The total energy of a simple pendulum i...

The total energy of a simple pendulum is x. When the displacement is half of amplitude,its KE will be

A

`(x)/(2)`

B

`(x)/(4)`

C

`(3x)/(4)`

D

`x`

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The correct Answer is:
To solve the problem, we need to determine the kinetic energy (KE) of a simple pendulum when its displacement is half of the amplitude. The total energy (TE) of the pendulum is given as \( x \). ### Step-by-Step Solution: 1. **Understanding the Energy of the Pendulum**: The total mechanical energy \( E \) of a simple pendulum is constant and is given by the sum of its kinetic energy \( KE \) and potential energy \( PE \): \[ E = KE + PE \] 2. **Define the Amplitude and Displacement**: Let the amplitude of the pendulum be \( A \). According to the problem, the displacement \( d \) is half of the amplitude: \[ d = \frac{A}{2} \] 3. **Calculate Potential Energy at Displacement**: The potential energy \( PE \) at a displacement \( d \) can be calculated using the formula: \[ PE = mgh \] For small angles, we can approximate \( h \) (the height) using the formula: \[ h = A - \sqrt{A^2 - d^2} \] Substituting \( d = \frac{A}{2} \): \[ h = A - \sqrt{A^2 - \left(\frac{A}{2}\right)^2} = A - \sqrt{A^2 - \frac{A^2}{4}} = A - \sqrt{\frac{3A^2}{4}} = A - \frac{\sqrt{3}}{2}A = A\left(1 - \frac{\sqrt{3}}{2}\right) \] 4. **Calculate Total Energy**: The total energy \( E \) is given as \( x \). At maximum displacement (amplitude), the potential energy is maximum and equals the total energy: \[ E = \frac{1}{2}kA^2 \] where \( k \) is the spring constant equivalent for the pendulum. 5. **Calculate Kinetic Energy**: Now, we can express the kinetic energy \( KE \) as: \[ KE = E - PE \] Substituting the values we have: \[ KE = x - PE \] 6. **Finding the Kinetic Energy**: We can express the potential energy at \( d = \frac{A}{2} \) in terms of \( x \) and substitute: \[ PE = \frac{1}{2}k\left(\frac{A}{2}\right)^2 = \frac{1}{2}k\frac{A^2}{4} = \frac{1}{8}kA^2 \] Since \( E = \frac{1}{2}kA^2 = x \), we can relate \( kA^2 \) to \( x \): \[ PE = \frac{1}{8}\left(2x\right) = \frac{x}{4} \] Thus, \[ KE = x - \frac{x}{4} = \frac{3x}{4} \] ### Final Answer: The kinetic energy when the displacement is half of the amplitude is: \[ KE = \frac{3x}{4} \]
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