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If a particle is moving as vec(r) = ( v...

If a particle is moving as `vec(r) = ( vec(i) +2 vec(j))cosomega _(0) t ` then,motion of the particleis

A

Elliptical

B

Along a straight line

C

Periodic

D

Simple harmonic

Text Solution

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The correct Answer is:
To analyze the motion of the particle given by the vector equation \(\vec{r} = ( \hat{i} + 2 \hat{j}) \cos(\omega_0 t)\), we can break down the problem step by step. ### Step 1: Identify the Components of Motion The position vector can be expressed in terms of its components: \[ \vec{r} = x \hat{i} + y \hat{j} \] where \(x = \cos(\omega_0 t)\) and \(y = 2 \cos(\omega_0 t)\). ### Step 2: Relate the Components From the expressions for \(x\) and \(y\), we can establish a relationship: \[ y = 2x \] This indicates that the motion of the particle is constrained to a linear relationship between \(x\) and \(y\). ### Step 3: Determine the Type of Motion The equation \(y = 2x\) represents a straight line in the \(xy\)-plane. Therefore, the motion of the particle is along a straight line. ### Step 4: Analyze the Periodicity The function \(\cos(\omega_0 t)\) is periodic with a period \(T = \frac{2\pi}{\omega_0}\). Since both \(x\) and \(y\) depend on this periodic function, the motion of the particle is periodic. ### Step 5: Check for Simple Harmonic Motion (SHM) The general form of simple harmonic motion is given by: \[ x = A \cos(\omega_0 t) \] For our case: - \(x = \cos(\omega_0 t)\) (which is SHM with amplitude 1) - \(y = 2 \cos(\omega_0 t)\) (which is also SHM with amplitude 2) Since both components exhibit simple harmonic motion, the overall motion can be considered as a combination of two simple harmonic motions in the \(x\) and \(y\) directions. ### Step 6: Resultant Motion The resultant motion can be analyzed using the Pythagorean theorem. The resultant amplitude can be calculated as: \[ R = \sqrt{(1)^2 + (2)^2} = \sqrt{5} \] The angle \(\theta\) with respect to the \(x\)-axis can be determined using: \[ \tan(\theta) = \frac{y}{x} = 2 \implies \theta = \tan^{-1}(2) \] Thus, the particle performs simple harmonic motion along a straight line at an angle \(\theta\). ### Conclusion The motion of the particle is: 1. Along a straight line. 2. Periodic. 3. Simple harmonic motion.
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