STATEMENT-1`:` Time period of a physical pendulum is independent of mass of the body.
STATEMENT-2 `:` Time period of a torsional pendulum is `2pi sqrt((l)/(k))` where, `l=` moment of inertia and` k=` Torsional constant.
STATEMENT-3 `:` S.H.M. is an example of non-uniform motion.

Options

A. T.T.T
B. F.T.F.
C. T.F.F.
D. F.F.F

Answer

To analyze the statements provided in the question, we will evaluate each statement one by one and determine their validity.

### Step 1: Evaluate Statement 1
**Statement 1:** "Time period of a physical pendulum is independent of mass of the body."

The formula for the time period \( T \) of a physical pendulum is given by:

\[ T = 2\pi \sqrt{\frac{I}{mgh}} \]

where:
- \( I \) is the moment of inertia,
- \( m \) is the mass,
- \( g \) is the acceleration due to gravity,
- \( h \) is the distance from the pivot to the center of mass.

From this formula, we can see that the time period \( T \) depends on the moment of inertia \( I \) and the distance \( h \), but the mass \( m \) cancels out when considering the ratio of \( I \) to \( mgh \). Therefore, the time period is indeed independent of the mass of the body.

**Conclusion:** Statement 1 is **True**.

### Step 2: Evaluate Statement 2
**Statement 2:** "Time period of a torsional pendulum is \( 2\pi \sqrt{\frac{I}{k}} \) where \( I \) is the moment of inertia and \( k \) is the torsional constant."

The formula for the time period \( T \) of a torsional pendulum is derived from the equation of motion for rotational systems. The torque \( \tau \) is related to the angular displacement \( \theta \) by:

\[ \tau = -k\theta \]

Using Newton's second law for rotation, we have:

\[ \tau = I\alpha \]

where \( \alpha \) is the angular acceleration. Setting these equal gives:

\[ I\alpha = -k\theta \]

This can be rewritten as:

\[ \alpha = -\frac{k}{I}\theta \]

This is in the form of simple harmonic motion, where \( \omega^2 = \frac{k}{I} \). The time period \( T \) is then:

\[ T = 2\pi \sqrt{\frac{I}{k}} \]

Thus, Statement 2 is also valid.

**Conclusion:** Statement 2 is **True**.

### Step 3: Evaluate Statement 3
**Statement 3:** "S.H.M. is an example of non-uniform motion."

Simple Harmonic Motion (S.H.M.) is characterized by a restoring force that is proportional to the displacement and directed towards the equilibrium position. The acceleration \( a \) in S.H.M. is given by:

\[ a = -\omega^2 x \]

Since the acceleration is not constant (it varies with displacement \( x \)), S.H.M. is indeed a type of accelerated motion. Thus, it is classified as non-uniform motion.

**Conclusion:** Statement 3 is **True**.

### Final Conclusion
All three statements are true. Therefore, the correct option is that all statements are true.

---