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A sound wave of wavelength 0.40 m enter...

A sound wave of wavelength `0.40 m` enters the tube at `S`. The smallest radius `r` of the circular segment to hear minimum at detector `D` must be

Text Solution

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The path difference between the waves moving along the straight path and the semicircular path is given by
`Deltaxpir-2r=(pi-2)r`
For minima this path difference should be at least `(lamda)/(2)` i.e., 20, hence we have, for the minimum value of r.
`(pi-2)r=20cm`
or `r=(20)/(pi-2)=17.54cm`
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