Waves of wavelength `lamda` are generated on the water surface. The phase difference between two points at a distance of `lamda` is

Options

A. `pi` radian
B. `2pi` radian
C. `(pi)/(2)` radian
D. `(pi)/(6)` radian

Answer

To find the phase difference between two points at a distance of wavelength \( \lambda \), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Phase Difference**:
The phase difference \( \Phi \) between two points in a wave can be calculated using the formula:
\[ \Phi = \frac{2\pi}{\lambda} \times \text{(path difference)} \]
where \( \lambda \) is the wavelength of the wave.

2. **Identify the Path Difference**:
In this problem, the path difference is given as \( \lambda \).

3. **Substitute the Path Difference into the Formula**:
Substitute the path difference into the phase difference formula:
\[ \Phi = \frac{2\pi}{\lambda} \times \lambda \]

4. **Simplify the Expression**:
When we simplify the expression, the \( \lambda \) in the numerator and denominator cancels out:
\[ \Phi = 2\pi \]

5. **Conclusion**:
Therefore, the phase difference between the two points at a distance of \( \lambda \) is:
\[ \Phi = 2\pi \text{ radians} \]

### Final Answer:
The phase difference between two points at a distance of \( \lambda \) is \( 2\pi \) radians.

---