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At room temperature (27^(@)C) the veloci...

At room temperature `(27^(@)C)` the velocity of sound in air is 330 m/s. the increase in velocity of sound when temperature is increased by `1^(@)C` is

A

2 m/s

B

1 m/s

C

10 m/s

D

0.55 m/s

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The correct Answer is:
To solve the problem of finding the increase in the velocity of sound in air when the temperature is increased by \(1^\circ C\), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between velocity of sound and temperature**: The velocity of sound in air is given by the formula: \[ V = \sqrt{\frac{\gamma RT}{M}} \] where: - \(V\) is the velocity of sound, - \(\gamma\) is the adiabatic index (approximately 1.4 for air), - \(R\) is the universal gas constant, - \(T\) is the absolute temperature in Kelvin, - \(M\) is the molar mass of air. 2. **Convert the given temperature to Kelvin**: The room temperature is given as \(27^\circ C\). To convert this to Kelvin: \[ T_1 = 27 + 273 = 300 \, K \] 3. **Calculate the new temperature after increasing by \(1^\circ C\)**: The new temperature \(T_2\) after an increase of \(1^\circ C\) will be: \[ T_2 = 27 + 1 + 273 = 301 \, K \] 4. **Use the formula for velocity at both temperatures**: The velocity of sound at \(T_1\) (300 K) is given as \(V_1 = 330 \, m/s\). We can express the velocities at both temperatures: \[ V_1 = \sqrt{\frac{\gamma R T_1}{M}} \quad \text{and} \quad V_2 = \sqrt{\frac{\gamma R T_2}{M}} \] 5. **Find the ratio of velocities**: Since \(\gamma\), \(R\), and \(M\) are constants, we can find the ratio of the velocities: \[ \frac{V_2}{V_1} = \sqrt{\frac{T_2}{T_1}} = \sqrt{\frac{301}{300}} \] 6. **Calculate \(V_2\)**: Now substituting \(V_1 = 330 \, m/s\): \[ V_2 = V_1 \cdot \sqrt{\frac{301}{300}} = 330 \cdot \sqrt{\frac{301}{300}} \] Approximating \(\sqrt{\frac{301}{300}} \approx 1.005\): \[ V_2 \approx 330 \cdot 1.005 \approx 331.65 \, m/s \] 7. **Calculate the increase in velocity**: The increase in velocity \(\Delta V\) is: \[ \Delta V = V_2 - V_1 = 331.65 - 330 = 1.65 \, m/s \] ### Final Answer: The increase in the velocity of sound when the temperature is increased by \(1^\circ C\) is approximately \(1.65 \, m/s\). ---
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