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An ideal gas follows a cyclic process as...

An ideal gas follows a cyclic process as shown in figure. Internal energy of gas at point A is 10 J while at B is 70 J. the heat absorbed by gas in BC is 120 J.
(a) How much heat is absorbed in process AB?
(b) Find heat energy rejected or absorbed by gas in process CA.

Text Solution

Verified by Experts

(a) Process AB is isobaric. For AB process,
`DeltaU=U_(B)-U_(A)=60J`
`W=PDeltaV=20(6-2)=80J`
`impliesQ_(AB)=DeltaU+W=60+80=140J`
(b) Net area enclosed by ABCA=net work done (which is negative since process is anticlockwise)
`impliessumW=-(1)/(2)xx40xx4=-80J`
For any cyclic process,
`sumQ=sumW` ltBrgt `impliesQ_(AB)+Q_(BC)+Q_(CA)=-80`
`implies140+120+Q_(CA)=-80`
`impliesQ_(CA)=-340J`.
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