If the boiling point of water is `95^(@)F`, what will be reduction at celsius scale?

Options

A. `7^(@)C`
B. `65^(@)C`
C. `63^(@)C`
D. `35^(@)C`

Answer

To find the reduction in the Celsius scale when the boiling point of water is given as 95°F, we can follow these steps:

### Step 1: Understand the conversion formula
The formula to convert Fahrenheit (°F) to Celsius (°C) is:
\[ °C = \frac{5}{9} (°F - 32) \]

### Step 2: Substitute the given value
We know the boiling point of water is 95°F. We will substitute this value into the formula:
\[ °C = \frac{5}{9} (95 - 32) \]

### Step 3: Calculate the difference
First, calculate \(95 - 32\):
\[ 95 - 32 = 63 \]

### Step 4: Multiply by \(\frac{5}{9}\)
Now, substitute this difference back into the formula:
\[ °C = \frac{5}{9} \times 63 \]

### Step 5: Perform the multiplication
Calculating \(\frac{5 \times 63}{9}\):
\[ 5 \times 63 = 315 \]
Now divide by 9:
\[ \frac{315}{9} = 35 \]

### Step 6: Conclusion
Thus, the boiling point of water at 95°F corresponds to 35°C. Therefore, the reduction at the Celsius scale is:
\[ \text{Reduction} = 100°C - 35°C = 65°C \]

### Final Answer
The reduction at the Celsius scale is 65°C.

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