Home
Class 12
PHYSICS
When a strip made or iron (alpha(1)) and...

When a strip made or iron `(alpha_(1))` and copper `(alpha_(2)),(alpha_(2) gt alpha_(1))` is heated

A

its length does not change

B

it gets twisted

C

it bends with iron on concave side

D

it bends with iron on convex side

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what happens when a strip made of iron and copper is heated, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a strip made of two different metals: iron (with coefficient of linear expansion \( \alpha_1 \)) and copper (with coefficient of linear expansion \( \alpha_2 \)). We know that \( \alpha_2 > \alpha_1 \), meaning copper expands more than iron when heated. 2. **Define the Coefficients of Linear Expansion**: The coefficient of linear expansion (\( \alpha \)) is defined as the fractional change in length per degree change in temperature. For a given length \( L \) and temperature change \( \Delta T \), the change in length \( \Delta L \) can be expressed as: \[ \Delta L = \alpha L \Delta T \] 3. **Apply the Concept to Each Metal**: - For copper, the change in length when heated is: \[ \Delta L_{\text{copper}} = \alpha_2 L \Delta T \] - For iron, the change in length when heated is: \[ \Delta L_{\text{iron}} = \alpha_1 L \Delta T \] 4. **Compare the Changes in Length**: Since \( \alpha_2 > \alpha_1 \), we can conclude: \[ \Delta L_{\text{copper}} > \Delta L_{\text{iron}} \] This means that copper will expand more than iron when the strip is heated. 5. **Determine the Effect on the Strip**: Because copper expands more than iron, the strip will bend. The side with the greater expansion (copper) will push outward, while the side with less expansion (iron) will not extend as much. 6. **Identify the Direction of Bending**: The bending will occur such that the iron side will be on the concave side (the inside of the bend) and the copper side will be on the convex side (the outside of the bend). Thus, the strip will bend with iron on the concave side and copper on the convex side. 7. **Conclusion**: Therefore, the correct statement regarding the behavior of the strip when heated is that it bends with iron on the concave side. ### Final Answer: The strip bends with iron on the concave side. ---
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-A) Objective Type questions (one option is correct)|50 Videos
  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-B) Objective Type questions (one option is correct)|15 Videos
  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J) Akash Challengers Questions|7 Videos
  • TEST2

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|2 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -D) (Assertion - Reason Type Questions)|10 Videos

Similar Questions

Explore conceptually related problems

A bimetallic strip of thickness d and length L is clamped at one end at temperature t_(1) . Find the radius of curvature of the strip if it consists of two different metals of expansivity alpha_(1) and alpha_(2) (alpha_(1) gt alpha_(2) ) when its temperature rises to t_(2) "^(@)C .

If f(x+y)=f(x).f(y) for all x and y, f(1) =2 and alpha_(n)=f(n),n""inN , then the equation of the circle having (alpha_(1),alpha_(2))and(alpha_(3),alpha_(4)) as the ends of its one diameter is

If 1,alpha_(1),alpha_(2),alpha_(3),...,alpha_(n-1) are n, nth roots of unity, then (1-alpha_(1))(1-alpha_(2))(1-alpha_(3))...(1-alpha_(n-1)) equals to

A bimetallic strip made of aluminium and steel (alpha_(Al) gt alpha_(steel)) on heating the strip will

A bimetallic strip made of aluminum and steel (alpha_(Al) gt alpha_(steel)) on heating the strip will a) remain straight b) get twisted c) will bend with aluminum on concave side d) will bend with steel on concave side.

If the roots of equation x^(3) + ax^(2) + b = 0 are alpha _(1), alpha_(2), and alpha_(3) (a , b ne 0) . Then find the equation whose roots are (alpha_(1)alpha_(2)+alpha_(2)alpha_(3))/(alpha_(1)alpha_(2)alpha_(3)), (alpha_(2)alpha_(3)+alpha_(3)alpha_(1))/(alpha_(1)alpha_(2)alpha_(3)), (alpha_(1)alpha_(3)+alpha_(1)alpha_(2))/(alpha_(1)alpha_(2)alpha_(3)) .

If 1, alpha_(1), alpha_(2), alpha_(3),…….,alpha_(s) are ninth roots of unity (taken in counter -clockwise sequence in the Argard plane). Then find the value of |(2-alpha_(1))(2-alpha_(3)),(2-alpha_(5))(2-alpha_(7)) |.

The maximum value of (cosalpha_(1))(cos alpha_(2))...(cosalpha_(n)), under the restrictions 0lealpha_(1),alpha_(2)...,alpha_(n)le(pi)/(2) and (cotalpha_(1))(cotalpha_(2))......(cotalpha_(n))=1 is

The variance of observation x_(1), x_(2),x_(3),…,x_(n) is sigma^(2) then the variance of alpha x_(1), alpha x_(2), alpha x_(3),….,alpha x_(n), (alpha != 0) is

let |{:(1+x,x,x^(2)),(x,1+x,x^(2)),(x^(2),x,1+x):}|=(1)/(6)(x-alpha_(1))(x-alpha_(2))(x-alpha_(3))(x-alpha_(4)) be an identity in x, where alpha_(1),alpha_(2),alpha_(3),alpha_(4) are independent of x. Then find the value of alpha_(1)alpha_(2)alpha_(3)alpha_(4)