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Two bodies A and B have thermal emissivi...

Two bodies A and B have thermal emissivities of 0.01 and 0.81 respectively. The outer surface areas of the two bodies are same. The two bodies emit total radiant power at the same rate. The wavelength `lambda_B` corresponding to maximum spectral radiancy from B is shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A by 1.0 `mum`. If the temperature of A is 5802 K, calculate (a) the temperature of B, (b) wavelength `lambda_B`.

A

The temperature of B is 1934 K

B

`lamda_(B)=1.5mum`

C

The temperature of B is 2901 K

D

The temperature of B is 2901 K

Text Solution

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The correct Answer is:
A, B
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  • IF the temperature of a black , body is doubled, the wavelength at which the spectral radiancy has its maximum is

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    B
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