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Two identical beakers with negligible th...

Two identical beakers with negligible thermal expansion are filled with water to the same level at `4^(@)C`. If one says `A` is heated while the other says `B` is cooled, then:

A

water level in A will rise

B

Water level in B will rise

C

Water level in A will fall

D

Water level in B will fall

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the behavior of water in two identical beakers when one is heated and the other is cooled, starting from the same initial temperature of 4°C. ### Step-by-Step Solution: 1. **Understanding the Initial Condition**: - Both beakers A and B are filled with water at 4°C. At this temperature, water has its maximum density (approximately 1 g/cm³) and minimum volume for a given mass of water. 2. **Heating Beaker A**: - When beaker A is heated, the temperature of the water increases above 4°C. As the temperature of water rises, its density decreases. This means that for the same mass of water, the volume will increase. 3. **Cooling Beaker B**: - When beaker B is cooled, the temperature of the water decreases below 4°C. Similar to the previous case, the density of water decreases as the temperature drops below 4°C. Therefore, the volume of water in beaker B will also increase. 4. **Comparing the Effects**: - In both cases (heating in A and cooling in B), the volume of water in each beaker increases. Since both beakers are identical and filled to the same level initially, the water level in both beakers will rise. 5. **Conclusion**: - The final outcome is that the water level in beaker A will rise due to heating, and the water level in beaker B will also rise due to cooling. ### Final Answer: The water level in beaker A will rise, and the water level in beaker B will also rise. ---
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