The horizontal component of earth's magnetic field at a certain place is ` 3xx 10^(-5) T` and the direction of the field is from the geographic south to the geographic north. A very long straight conductor is carrying a steady current of 1 A. What is the force per unit length on it when it is placed on a horizontal table and the direction of current is from east to west ?

Explanation

To solve the problem, we need to find the force per unit length on a long straight conductor carrying a current in a magnetic field. Here are the steps to arrive at the solution:

### Step 1: Identify the given values
- Horizontal component of Earth's magnetic field, \( B = 3 \times 10^{-5} \, \text{T} \)
- Current in the conductor, \( I = 1 \, \text{A} \)
- Direction of the magnetic field is from geographic south to geographic north.
- Direction of the current is from east to west.

...