Home
Class 12
PHYSICS
A proton and an alpha-particle, accelera...

A proton and an `alpha`-particle, accelerated through same potential difference, enter a region of uniform magnetic field with their velocities perpendicular to the field. Compare the radii of circular paths followed by them.

Text Solution

AI Generated Solution

To compare the radii of the circular paths followed by a proton and an alpha particle when both are accelerated through the same potential difference and enter a uniform magnetic field perpendicularly, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Charges and Masses**: - The charge of a proton (Q) is \( q \). - An alpha particle consists of 2 protons and 2 neutrons, giving it a charge of \( 2q \) and a mass of approximately \( 4m \) (where \( m \) is the mass of a proton). ...
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Illustration|14 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|27 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos
  • NUCLEI

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|10 Videos

Similar Questions

Explore conceptually related problems

A proton and an alpha particle accellerated throught the same potential differenc e enter a region of uniform magnetic field normally if the radius of the proton orbit is 10 cm ten radius of alpha particle is

A proton, a deutron and an alpha particle, after being accelerated through the same potential difference enter a region of uniform magnetic field vecB , in a direction perpendicular to vecB . Find the ratio of their kinetic energies. If the radius of proton's circular path is 7cm , what will be the radii of the paths of deutron and alpha particle?

A proton, a deutron and an alpha - particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to it. What is the ratio of their kinetic energy?

A charged particle of mass m and charge q is accelerated through a potential difference of V volts. It enters a region of uniform magnetic field which is directed perpendicular to the direction of motion of the particle. Find the radius of circular path moved by the particle in magnetic field.

A proton and alpha - particle are accelerated with same potential difference and they enter in the region of constant magnetic field B perpendicular to the velocity of particles. Find the ratio of radius of curvature of alpha - particle .

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

A proton, a deuteron and an alpha particle, are accelerated through the same potential difference and then subjected to a unifrom magnetic field vecB , perpendicular to the direction of their motions. Compare (i) their kinetic energies, and (ii) if the radius of the ciruclar path described by proton is 5 cm, determine the radii of the paths described by deuteron and alpha partcile.

An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is

A proton and an alpha - Particle ( with their masses in the ratio of 1:4 and charges in the ratio of 1:2 ) are accelerated form rest through a potential differeence V, if a uniform magnetic field (B) is set up perpendicular to their velocities , the ratio of the radii r_(p) : r_(alpha) of the circular paths described by them will be :