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A current carrying conductor of length l...

A current carrying conductor of length `l` is bent into two loops one by one. First loop has one turn of wire and the second loop has two turns of wire. Compare the magnetic fields at the centre of the loops

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To compare the magnetic fields at the center of two loops formed by a current-carrying conductor of length \( L \), we can follow these steps: ### Step 1: Determine the radius of the first loop For the first loop, which has one turn, the circumference is equal to the length of the wire: \[ 2\pi r_1 = L \] From this, we can solve for the radius \( r_1 \): ...
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