Write equation for Ampere's circuital law for the Amperian loop shown (traversed in the direction shown by arrow marks put on it)

Explanation

If seen from top, left side portion of the loop is traversed anticlockwise, while the other portion is traversed clockwise. Thus by sign convention: `i_(1)` is positive `i_(2)` is positive `i_(3)` is negative
Thus, `oint vec(B). vec(dl) = mu_(0)l`
`= mu_(0) (i_(1) + i_(2) - i_(3))`