Find the magnetic field at the ccentre of a current carrying conductor bent in the form of an arc subtending angle `theta` at its centre. Radius of the arc is R
Strategy: Let the arc lie in x-y plane with its centre at the origin. Consider a small current element `i vec(dl)` as shown. The field due to this element at the centre can be obtained by Biot-Savart law

Explanation

To find the magnetic field at the center of a current-carrying conductor bent in the form of an arc subtending an angle \( \theta \) at its center with a radius \( R \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have a current-carrying arc of radius \( R \) that subtends an angle \( \theta \) at the center. The arc lies in the x-y plane with its center at the origin.

2. **Applying the Biot-Savart Law**:
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