Home
Class 12
PHYSICS
Magnetic dipole moment of rectangular lo...

Magnetic dipole moment of rectangular loop is

A

Inversely proportional to current in loop

B

Inversely proportional to area of loop

C

Parallel to plane of loop and proportional to area of loop

D

Perpendicular to plane of loop and proportional to area of loop

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnetic dipole moment of a rectangular loop, we can follow these steps: ### Step 1: Understand the concept of magnetic dipole moment The magnetic dipole moment (\(m\)) is a vector quantity that represents the strength and direction of a magnetic source. For a current-carrying loop, it depends on the current flowing through the loop and the area enclosed by the loop. ### Step 2: Identify the formula for magnetic dipole moment The magnetic dipole moment for a rectangular loop can be expressed as: \[ m = n \cdot I \cdot A \] where: - \(m\) = magnetic dipole moment - \(n\) = number of turns in the loop - \(I\) = current flowing through the loop - \(A\) = area of the loop ### Step 3: Calculate the area of the rectangular loop For a rectangular loop with length \(l\) and width \(w\), the area \(A\) can be calculated as: \[ A = l \cdot w \] ### Step 4: Substitute the area into the magnetic dipole moment formula Substituting the area into the formula gives: \[ m = n \cdot I \cdot (l \cdot w) \] ### Step 5: Determine the direction of the magnetic dipole moment The direction of the magnetic dipole moment is given by the right-hand rule. If the current flows in a clockwise direction, the magnetic dipole moment points inward (toward the plane of the loop). If the current flows in an anti-clockwise direction, the magnetic dipole moment points outward (away from the plane of the loop). ### Step 6: Conclusion Thus, the magnetic dipole moment of a rectangular loop is given by: \[ m = n \cdot I \cdot A \] and it is perpendicular to the plane of the loop.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section B) Objective Type Questions (One option is correct)|35 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section C (Objective Type Questions (More than one option are correct)|14 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|27 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos
  • NUCLEI

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|10 Videos

Similar Questions

Explore conceptually related problems

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m .If this square loop is changed to a circular loop and it carries the same current the magnitude of the magnetic dipole moment of circular loop will be

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. if this square loop is changed to a circular loop and it carries the current, the magnitude of the magnetic dipole moment of circular loop will be :

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. if this square loop is changed to a circular loop and it carries the current, the magnitude of the magnetic dipole moment of circular loop will be :

The magnetic dipole moment of current loop is independent of

In the given option,the magnetic dipole moment of current loop is independent of

A current of 10.0 nA is established in a circular loop of radius 5.0 cm. find the magnetic dipole moment of the current loop. : The magnetic dipole moment is vec mu= veciA .

The ratio of magnetic dipole moment to angular momentum of electron is

Compute the magnetic dipole moment of the loop shown in Fig. 1.69

The magnetic dipole moment of a current carrying conducting loop depends on

A current loop, carrying a current of 5.0 A, is in the shape of a right triangle with sides 30,40, and 50 cm. The loop is in a uniform magnetic field of magnitude 80 mT whose direction is parallel to the current in the 50 cm side of the loop. Find the magnitude of (a) the magnetic dipole moment of the loop and (b) the torque on the loop.