A short bar magnet is kept in uniform magnetic field of `0.16` T such that dipole moment vector is at angle `30^(@)` with the field . The torque acting on the bar magnet is 0.032 N m . What is the magnitude of magnetic dipole moment of the magnet ?

Explanation

To find the magnitude of the magnetic dipole moment (M) of the bar magnet, we can use the formula for the torque (τ) acting on a magnetic dipole in a magnetic field:

\[ \tau = M B \sin \theta \]

Where:
- \( \tau \) = torque (in N·m)
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