A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equilibrium . If it is rotated through `30^(@)` , find its potential energy in new position [Given , B = 0.2 T]

Explanation

To find the potential energy of a bar magnet in a magnetic field after it has been rotated through an angle, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values**:
- Magnetic dipole moment (M) = 10 Am²
- Magnetic field (B) = 0.2 T
- Angle (θ) = 30°
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