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A magnetic needle suspended in a vertical plane at `30^@` from the magnetic meridian makes an angle of `45^@` with the horizontal. Find the true angle of dip.

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Verified by Experts

`tan 45^(@) = (tan delta)/(cos 30^(@))`
`1 = (2 tan delta)/(sqrt3)`
`delta = tan^(-1) ((sqrt3)/(2))`
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