A magnet is pointing towards geographic north at a place where horizontal component of earth's magnetic field is `40 mu T ` . Magnetic dipole moment of the bar magnet is `60 Am^(2)` and torque acting on the magnet is `1.2 xx 10^(-3) N` m . What is declination at this place ?

Explanation

To find the declination at the given place, we will use the relationship between torque, magnetic dipole moment, magnetic field, and the angle of declination. Here’s the step-by-step solution:

### Step 1: Understand the given values
- Horizontal component of Earth's magnetic field, \( B_H = 40 \, \mu T = 40 \times 10^{-6} \, T \)
- Magnetic dipole moment of the bar magnet, \( M = 60 \, A m^2 \)
- Torque acting on the magnet, \( \tau = 1.2 \times 10^{-3} \, N \cdot m \)

### Step 2: Write the formula for torque
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